Study on the flySATMathSystems of two linear equations in two variables

Systems of two linear equations in two variables — SAT practice questions

Practice 82 Systems of two linear equations in two variables questions in the app

What this topic is

Systems of two linear equations in two variables on SAT Math covers finding the ordered pair that satisfies both equations, plus the cases of no solution and infinitely many solutions.

A student must solve by substitution or elimination, model a quantity-and-price story as equations, and sometimes find a combination of the unknowns. The SAT often asks which second equation would yield infinitely many solutions, requests a derived value from a solved pair, or hides the system in a sales story.

Traps include confusing a unique solution with a dependent system and stopping after one variable. Answer choices are typically other linear equations or single values.

Sample questions

Pick an answer to see whether it is right — nothing is saved, and nothing needs an account.

Question 1Easier

4x+3y=534x+3y=53
3x+2y=343x+2y=34

The solution to the given system of equations is (x,y)(x, y). What is the value of x+yx+y?

Show answer

Answer: C — 19

Subtracting the second equation from the first gives (4x+3y)(3x+2y)=5334(4x+3y)-(3x+2y)=53-34, so x+y=19x+y=19.

Question 2Easier

7x+3y=117x+3y=-11

The given equation is one equation in a system of two linear equations. If the system has infinitely many solutions, which of the following equations could be the other equation in the system?

Show answer

Answer: B — 21x9y=33-21x-9y=33

Multiplying 7x+3y=117x+3y=-11 by 3-3 produces 21x9y=33-21x-9y=33. The equations therefore describe the same line, so every point on that line is a solution.

Question 3Easier

A campus shop sold pens for $2 each and notebooks for $3 each. Yesterday the shop sold a combined total of 55 pens and notebooks for $128. How many pens were sold?

Show answer

Answer: D — 37

Let pp be pens and nn notebooks. Then p+n=55p+n=55 and 2p+3n=1282p+3n=128. Substitute n=55pn=55-p: 2p+3(55p)=1282p+3(55-p)=1282p+1653p=1282p+165-3p=128p=37-p=-37p=37p=37.

Every question is picked for where you are right now, wrong answers come back until they stick, and it all works offline.

Practice 82 Systems of two linear equations in two variables questions in the app

More SAT topics

Everything on the SAT